A particle is projected from the ground with velocity u making an angle theta with the horizontal. At half of its maximum heights,

A particle is projected from the ground with velocity u making an angl

1.	A particle is projected from the ground with velocity u making an angle theta with the horizontal. At half of its maximum heights,
Answer» its horizontal VELOCITY is `ucos theta` its vertical velocity is `(u SIN theta)/(SQRT(2))` its velocity is `u((1+Cos^(2)theta)/(2))` all the above are true Answer :D