A particle is projected from the origin in X-Y plane. Acceleration of particle in Y direction is alpha. If equation of path of the particle is y = ax - bx^(2), then find initial velocity of the particle.

A particle is projected from the origin in X-Y plane. Acceleration of

1.	A particle is projected from the origin in X-Y plane. Acceleration of particle in Y direction is alpha. If equation of path of the particle is y = ax - bx^(2), then find initial velocity of the particle.
Answer» SOLUTION :`y = ax - bx^(2) ""y = x TAN THETA - (alpha x^(2))/(2U^(2) cos^(2) theta)` `tan theta = a` and `(alpha)/(2u^(2) cos^(2) theta) = b ""u = sqrt((alpha(1+a^(2)))/(2B))`