A particle is projected from the origin in X-Y plane. Acceleration of particle in Y direction is alpha. If equation of path of the particle is y=ax-bx^(2), then find initial velocity of the particle.

A particle is projected from the origin in X-Y plane. Acceleration of

1.	A particle is projected from the origin in X-Y plane. Acceleration of particle in Y direction is alpha. If equation of path of the particle is y=ax-bx^(2), then find initial velocity of the particle.
Answer» SOLUTION :`y=ax-bx^(2)""y=xtantheta-(alphax^(2))/(2U^(2)cos^(2)theta)` `tantheta=a and (alpha)/(2u^(2)cos^(2)theta)=b""usqrt((alpha(1+a^(2)))/(2B))`.