1.

A particle is projected in `x-y` plane with `y-`axis along vertical, the point of projection being origin. The equation of projectile is `y = sqrt(3) x - (gx^(2))/(2)`. The angle of projectile is ……………..and initial velocity si ………………… .

Answer» Correct Answer - `60,2 m//sec`
`y = sqrt(3) x - (gx^(2))/(2)` comparing with
`y = tan theta.x - (1)/(2) (gx^(2))/(u^(2)cos^(2) theta)`
`tan theta = sqrt(3) rArr theta = 60^(@)`
`u^(2) cos^(2) theta = 1 rArr u^(2) xx (1)/(4) = 1`
`u = 2m//s`


Discussion

No Comment Found

Related InterviewSolutions