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A particle is projected in `xy` plane with `y`-axis along vertical, the point of projection is origin. The equation of the path is `y=sqrt3x-g/2x^(2)`.where `y` and `x` are in `m`.Then the speed of projection in `ms^(-1)` isA. 2B. `sqrt3`C. 4D. `sqrt3/2` |
Answer» Correct Answer - A Compare the equation with `y=x tan theta-g/(2u^(2)cos^(2) theta)x^(2)` |
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