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A particle is projected on an inclined plane with a speed `u` as shown in (Fig. 5.61). Find the range of the particle on the inclined plane. . |
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Answer» `R = (u^2)/(g cos^2 theta_0) [sin(2 prop + theta_0) - sin theta_0]` where `theta_0 = 30^@ and prop = 45^@` Then, `R = (u^2)/(g cos^2 30^@) [sin(2 xx 45^@ + 30^@)- sin30^(@)]` =`(2 u^2sqrt(3 - 1))/(3 g)`. |
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