A particle is projected up into air from a point with a speed of20 m//s at an. angle of projection 30^@. What is the maximum height reached by it?

A particle is projected up into air from a point with a speed of20 m//

1.	A particle is projected up into air from a point with a speed of20 m//s at an. angle of projection 30^@. What is the maximum height reached by it?
Answer» SOLUTION :`H=(mu^2sin^2theta)/(2G)=((20)^2xx(SIN30^@)^2)/(2xx9.8)=5.1m`