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A particle is projected vertically upwards from the earth. It crosses the same point at t=2 sec and t=8 sec. Find out `[g=10 ms^(-2)]` (i) the time for which particle remains in air (ii) intial velocity of particle (iii) maximum height attained by the particle (iv) height of the particle at t=2 sec and t=8 sec from earth |
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Answer» Correct Answer - (i) 10 sec (ii) 50 m//s (iii) 125 m (iv) 80 m |
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