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A particle is projected vertically upwards with a speed of `16ms^-1`. After some time, when it again passes through the point of projection, its speed is found to be `8ms^-1`. It is known that the work done by air resistance is same during upward and downward motion. Then the maximum height attained by the particle is (take `g=10ms^-2`)A. (a) `8m`B. (b) `4.8m`C. (c) `17.6m`D. (d) `12.8m` |
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Answer» Correct Answer - A From work-energy theorem, for upward motion `1/2m(16)^2=mgh+W` (work done by air resistance) for downward motion, `1/2m(8)^2=mgh-Wimplies1/2[(16)^2+(8)^2]=2gh` or `h=8m` |
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