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A particle is projected with `20ms^(-1)` at `30^(@)` above horizontal. Find ratio of maximum height to the range of the projectile.A. `(1)/(4sqrt(3))`B. `sqrt(3)/(4)`C. `4sqrt(3)`D. `(4)/sqrt(3)` |
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Answer» `H=(u^(2)sin^(2)theta)/(2g)` `R=(v^(2)s2intheta)/(g)` `(H)/(R)-(tan theta)/(4)` |
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