A particle is released at point P(−2 m,2 m) on a smooth parabolic track given by y=x22. It slides down the track and leaves the contact with the track at point Q(1 m,0.5 m), and then slides till point R along QR. Distance QR in m equals (g=10 m/s2)

A particle is released at point P(−2 m,2 m) on a smooth parabolic tr

1.	A particle is released at point P(−2 m,2 m) on a smooth parabolic track given by y=x22. It slides down the track and leaves the contact with the track at point Q(1 m,0.5 m), and then slides till point R along QR. Distance QR in m equals (g=10 m/s2)
Answer» A particle is released at point $P (- 2 m, 2 m)$ on a smooth parabolic track given by $y = \frac{x^{2}}{2}$ . It slides down the track and leaves the contact with the track at point $Q (1 m, 0.5 m)$ , and then slides till point $R$ along $Q R$ . Distance $Q R$ in m equals $(g = 10 {m/s}^{2})$

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A particle is released at point P(−2 m,2 m) on a smooth parabolic track given by y=x22. It slides down the track and leaves the contact with the track at point Q(1 m,0.5 m), and then slides till point R along QR. Distance QR in m equals (g=10 m/s2)

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