Saved Bookmarks
| 1. |
A particle is released from a height h. At a certain height, its kinetic energy is two times its potential energy. Height and speed of the particle at that instant are |
|
Answer» `h/3 sqrt((2gh)/(3))` As `(KE)/(PE) = 2/1` `:. `KE = `2/3 mgh and PE = 1/3 mgh` Height from the ground at that INSTANT is `h. = h/3` and speed of particle at that instant is `V = sqrt(2G(h - h.)) = sqrt(2h((2h)/(3))) = 2sqrt((gh)/(3))`. |
|