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A particle is released from a height h. At a certain height, its kinetic energy is two times its potential energy. Height and speed of the particle at that instant are

Answer» <html><body><p>`h/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> sqrt((2gh)/(3))`<br/>`h/3 2sqrt((gh)/(3))`<br/>`(2h)/3 sqrt((2gh)/(3))`<br/>`h/3 sqrt(2gh)`</p>Solution :Total <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy = mgh <br/>As `(KE)/(PE) = 2/1`<br/>`:. `KE = `2/3 mgh and PE = 1/3 mgh` <br/> Height from the ground at that <a href="https://interviewquestions.tuteehub.com/tag/instant-1046099" style="font-weight:bold;" target="_blank" title="Click to know more about INSTANT">INSTANT</a> is `h. = h/3` <br/> and speed of particle at that instant is <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>(h - h.)) = sqrt(2h((2h)/(3))) = 2sqrt((gh)/(3))`.</body></html>


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