1.

A particle is released from a height h. At a certain height, its kinetic energy is two times its potential energy. Height and speed of the particle at that instant are

Answer»

`h/3 sqrt((2gh)/(3))`
`h/3 2sqrt((gh)/(3))`
`(2h)/3 sqrt((2gh)/(3))`
`h/3 sqrt(2gh)`

Solution :Total MECHANICAL energy = mgh
As `(KE)/(PE) = 2/1`
`:. `KE = `2/3 mgh and PE = 1/3 mgh`
Height from the ground at that INSTANT is `h. = h/3`
and speed of particle at that instant is
`V = sqrt(2G(h - h.)) = sqrt(2h((2h)/(3))) = 2sqrt((gh)/(3))`.


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