A particle is subjected to two simple harmonic motions given by x_1 = 2.0 sin(100 pi t) and x_2= 2.0 sin(120 pi t+pi//3) where x is in centimeter and t in second. Find the displacement of the particle at t= 0.0125.

A particle is subjected to two simple harmonic motions given by x_1 =

1.	A particle is subjected to two simple harmonic motions given by x_1 = 2.0 sin(100 pi t) and x_2= 2.0 sin(120 pi t+pi//3) where x is in centimeter and t in second. Find the displacement of the particle at t= 0.0125.
Answer» SOLUTION :`-2.41 CM `