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A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If `W_(nc)` and `W_c` are the work done by non-conservative and conservative forces present in the system, respectively, `DeltaU` is the change in potential energy and `Deltak` is the change in kinetic energy, thenA. (a) `W_(nc)-DeltaU=Deltak`B. (b) `W_c=-DeltaU`C. (c) `W_(nc)+W_(c)=Deltak`D. (d) `W_(nc)-DeltaU=-Deltak` |
Answer» Correct Answer - A::B::C According to the work-energy theorem for a non-conservative system, we have `W_c+W_(nc)=DeltaK` Also, we know that the work done by a conservative force equals the decrease in potential energy, so `W_c=-DeltaU` `W_(nc)-DeltaU=DeltaK` |
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