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A particle is thrown vertically upward with a speed `u` from the top of a tower of height `h` from ground level, If after first impact with ground it just reaches to height `h` from ground the coeffecient of restitution for the collision is `:-`A. `1`B. `u^(2)`C. `sqrt((2gh)/(U^(2)+2gh))`D. `sqrt(2gh)/(U)` |
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Answer» Correct Answer - C Ans.(3) Speed with which the particle hit the ground `v=sqrt(u^(2)+2gh)` As the particle just rises to height `h`, speed just after impact `v^(2)=sqrt(2gh)` But `v^(2)=cvrArre=(V^(t))/(V)=sqrt((2gh)/(U^(2)+2gh))` |
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