

InterviewSolution
Saved Bookmarks
1. |
A particle is thrown with a speed u at an angle θ to the horizontal. When the particle makes an angle ϕ with the horizontal, its speed changes to v.(a) v = ucos θ(b) v = ucos θ . cos ϕ(c) v = ucos θ . sec ϕ (d) v = usec θ . cos ϕ |
Answer» Correct answer is: (c) v = ucos θ . sec ϕ The horizontal component of the velocity remains constant. Hence, ucos θ . vcos ϕ. |
|