InterviewSolution
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InterviewSolution
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A particle is thrown with velocity `u` at an angle `prop` from the horizontal. Another particle is thrown with the same velocity at an angle `prop` from the verticle. What will be the ratio of times of flight of two particles ? |
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Answer» For first particles angle of projection from the hortizontal is `prop`. So `T_1 = (2usinprop)/(g)` For second particle, angle of projection from the vertical is `prop`. it mean from the horizontal is `(theta - prop)` `therefore T_(2) = (2 u sin(90 - prop))/(g) = (2 u cos prop)/(g)` So, ratio of time of flight `(T_1)/(T_2) = tan prop`. |
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