A particle is thrown with velocity u making an angle theta

1.	A particle is thrown with velocity u making an angle theta
Answer» times taken to reach P is\xa01s\xa0thereforev2=u2+2aSv2=u2cos2θ−2ghlet the distance from P to reach at the top be xv2=u2+2as0=u2cos2θ−2gh−2gxx=2gu2cos2θ\u200b−htime taken is\xa0v=u+at0=ucosθ−g−gtt=gucosθ\u200b−1time taken to reach top from P is\xa01s2g=ucosθmaximum height\xa0H=2gu2cos2θ\u200b\xa0as the verical component is\xa0ucosθtherefore\xa0H=2g(2g)2\u200b=2g=19.6m

Discussion