A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm . At what displacement from the equilibrium position, is its energy half potential and half kineticA. 1 cmB. `sqrt(2)` cmC. 3 cmD. `2sqrt(2)` cm

A particle is vibrating in a simple harmonic motion with an amplitude

1.	A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm . At what displacement from the equilibrium position, is its energy half potential and half kineticA. 1 cmB. `sqrt(2)` cmC. 3 cmD. `2sqrt(2)` cm
Answer» Correct Answer - D `U=K " or "U=(E)/(2)` `therefore (1)/(2)Kx^(2)=(1)/(2)((1)/(2)KA^(2))` i.e., at `x=+-(A)/(sqrt(2)),U=K` and this situation will occur for four times in one complete period.

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A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm . At what displacement from the equilibrium position, is its energy half potential and half kineticA. 1 cmB. `sqrt(2)` cmC. 3 cmD. `2sqrt(2)` cm

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