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A particle lies on the bottom of a tank `T` filled with water upto s height of `90 cm`. The medium above the surface of water is of `R.I = 1.2` above which there is mirror `M`. Beyond the mirror `M` the region contains air (`mu =1`). The distance of the image formed by the mirrro after reflection of the rays coming from `P` is ____ cm (w.r.t mirror). . |
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Answer» Correct Answer - 150 cm For refraction at water surface `u = - 90 cm rArr mu_(2) = 1.2` `mu_(1)=4//3 rArr v=(u mu_(2))/(mu_(1))=-81 cm` This image formed at `81 + 69 = 150 cm` below the mirror, after reflection from the mirror will form its new image `150 cm` above it. |
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