A particle moves according to the law x = a cos""(pit)/(2) .The distance covered by it in the timeinterval between t = 0 to t =3 sec is

A particle moves according to the law x = a cos""(pit)/(2) .The distan

1.	A particle moves according to the law x = a cos""(pit)/(2) .The distance covered by it in the timeinterval between t = 0 to t =3 sec is
Answer» Solution :COMPARING the given EQUATION with `x = a cosomegat IMPLIES omega= (pi)/(2) (2pi)/(T)= (pi)/(2) implies T= 4"sec"` The given time `t= 3"sec"` is really `(3T)/(4)` At time t=0 particleat x=a ( at extremeposition) and at `t=3 "sec" = (3T)/(4)` it will be at MEAN POSITION x=0 `:.` distance covered will be .3a..