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A particle moves along 1 ositive branch of the curve `y=(x)/(2)` where `x=(t^(3))/(3)`, x and y are measured in metres and t in seconds, then-A. the velocity of particle at t- 1 s is `hati+(1)/(2)hatj`B. the velocity of particle at t= 1 s is `(1)/(2)hati+hatj`C. the acceleration of particle at t=2s is `4hati+2hatj`D. the acceleration of particle at t=2s is `hati+2hatj` |
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Answer» `(dx)/(dt)=t^(2)` . . . ..(i) `y=(1)/(2)(t^(3))/(3)` `(dy)/(dt)=(t^(2))/(2)` `t=1,v_(x)=1,v_(y)=(1)/(2)` `vecv=hati+(1)/(2)hatj` `(d^(2)x)/(dt^(2))=2t` ltrbgt `(d^(2)y)/(dt^(2))=t` `"at" t=1s a_(x)=2 "and" a_(y)=1` `veca=2hati+hatj` |
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