1.

A particle moves along a circle if radius (`20 //pi`) m with constant tangential acceleration. If the velocity of the particle is ` 80 m//s` at the end of the second revolution after motion has begun the tangential acceleration is .A. `40 m//s^2`B. ` 640 pi //s^@`C. 1 60 mss^(2)`D. 40 m//s^2`

Answer» Correct Answer - A
` r= ( 20 // pi ) m , v= 80 m//s , `
` theta = 2 rev = 4 pi rad , omega _0=0`
From the equatin ` omega^2 =omega_0^2 + 2 alpha theta , we have
` moega^2 = 2 alpha theta ` or v^2/r^2 = 2 . A/ r theta`
` or ` a = u^2 /(2 r theta) = ( 80^2)/(2 xx (20 //pi ) xx 4 pi) = 40 m//s^2`.


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