1.

A particle moves along a straight line and itsvelocity at a distance 'x' from the orign isk \sqrt{a^{2}-x^{2}}. Then accelertion of the particle is

Answer»

v=kroot(a^2-x^2)a=dv/dt=k*(-2x)/(2root(a^2-x^2))=-kx/root(a^2-x^2)



Discussion

No Comment Found