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A particle moves along a straight line and itsvelocity at a distance 'x' from the orign isk \sqrt{a^{2}-x^{2}}. Then accelertion of the particle is |
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Answer» v=kroot(a^2-x^2)a=dv/dt=k*(-2x)/(2root(a^2-x^2))=-kx/root(a^2-x^2) |
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