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A particle moves along a straight line. Its position at any instant is given by `x = 32t-(8t^3)/3` where x is in metres and t in seconds. Find the acceleration of the particle at the instant when particle is at rest.A. `-16 ms^-2`B. `-32 ms^-2`C. `32 ms^-2`D. `16 ms^-2` |
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Answer» Correct Answer - B `v=(dx)/(dt)=32-8t^2` `v=0` at `t=2s` `a=(dv)/(dt)=-16t` at `t=2s, a=032m//s^2` |
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