A particle moves along the parabolic path y=2x−x2+2, in such a way that the x-component of velocity vector remains constant (5 m/s). Find the magnitude of acceleration of the particle.

A particle moves along the parabolic path y=2x−x2+2, in such a way t

1.	A particle moves along the parabolic path y=2x−x2+2, in such a way that the x-component of velocity vector remains constant (5 m/s). Find the magnitude of acceleration of the particle.
Answer» A particle moves along the parabolic path $y = 2 x - x^{2} + 2$ , in such a way that the x-component of velocity vector remains constant ( $5 m / s$ ). Find the magnitude of acceleration of the particle.

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A particle moves along the parabolic path y=2x−x2+2, in such a way that the x-component of velocity vector remains constant (5 m/s). Find the magnitude of acceleration of the particle.

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