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A particle moves along the positive branch of the curve `y = (x^(2))/(2)` where `x = (t^(2))/(2),x` and y are measured in metres and t in second. At `t = 2s`, the velocity of the particle isA. `2 hati - 4 hatj ms^(-1)`B. `4 hati +2 hatj ms^(-1)`C. `2 hati + 4hatj ms^(-1)`D. `4 hati - 2hatj ms^(-1)` |
Answer» Correct Answer - C As, `v_(x) = (dx)/(dt) = (2t)/(2) = t` At `2s, v_(x) = 2ms^(-1)` Further, `y = (x^(2))/(2) = ((t^(2)//2)^(2))/(2) = (t^(4))/(8) rArr v_(y) = (dy)/(dt) = (t^(3))/(2)` At `t = 2s, v_(y) = 4ms^(-1)` |
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