A particle moves along the x-axis in such a way that its coordinates x varies with time 't' according to the equation x=2-5t+6t^(2). What is the initial velocity of the particle?

A particle moves along the x-axis in such a way that its coordinates x

1.	A particle moves along the x-axis in such a way that its coordinates x varies with time 't' according to the equation x=2-5t+6t^(2). What is the initial velocity of the particle?
Answer» SOLUTION :`X=2-5t+6t^(2)` VELOCITY, `v=(DX)/(dt)=(d)/(dt)(2-5t+6t^(2))orv=-5+12t` For initial velocity, t=0 `:.` Initial velocity `=-5ms^(-1)` The negative sign implies that at t=0 the velocity of the particle is along negative x direction.