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A particle moves along the x-direction with constant acceleration. The displacement, measured from a convenient position, is 2 m at time `t= 0` and is zero when `t= 10 s.` If the velocity of the particle is momentary zero when `t = 6 s,` determine the acceleration a and the velocity v when `t= 10s.` |
Answer» Correct Answer - A::B `s=s_0+ut+1/2at^2` at `t=0, s=s_0=2m …(i)` at `t=10s,` `s=0=s_0+ut+1/2at^2` or `10u+50a=-2….(ii)` `v=u+at` `:. 0=u+at` `:. 0=u+6a (at t=6s)` `:. u+6a=0….(iii)` Solving Eqs. (ii) and (iii) we get, `u=-1.2 m//s` and `a=0.2 m//s^2` Now, `v=u+at` `:. v=(-12)+(0.2)(10)` `=0.8 m//s` |
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