1.

A particle moves from a point (- 2 hati + 5 hatj)to (4 hatj + 3hatk) when a force of (4 hati + 3hatj) N is applied. How much work has been done by the force?

Answer»

8J
11 J
5 J
2 J

Solution :Here, `vec(r_1) = (-2hati +5hatj) m, vec(r_2) = (4 hatj + 3 HATK)m`
`VECF = (4 hati + 3 hatj) N, W = ?`
Work done by force F in moving from `vec(r_1) ` to `vec(r_2)`
`W = vecF . (vec(r_2) - vec(r_1)) = (4hati + 3hatj) . (4 hatj + 3hatk + 2 hati - 5 hatj)`
`= (4 hati + 3 hatj) . (2 hati - hatj + 3 hatk) = 8 + (-3) = 5 J`.


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