A particle moves in a circular path such that its speed v varies with distance asv = alpha sqrt swhere a is a positive constant. Find the acceleration of particle after transversinga distance S?

A particle moves in a circular path such that its speed v varies with

1.	A particle moves in a circular path such that its speed v varies with distance asv = alpha sqrt swhere a is a positive constant. Find the acceleration of particle after transversinga distance S?
Answer» `ALPHA^2 SQRT(1/4 - S^2/R^2)` `alpha^2 sqrt(1/4+S^2/R^2)` `alpha sqrt(1/2 + S^2/R^2)` `alpha^2 sqrt(1/2 + S^2/R^2)` ANSWER :B