A particle moves in a circular path such that its speed v varies with distance as V= alphasqrt(s)where alpha is a positive constant. Find the acceleration of the particle after traversing a distance s.

A particle moves in a circular path such that its speed v varies with

1.	A particle moves in a circular path such that its speed v varies with distance as V= alphasqrt(s)where alpha is a positive constant. Find the acceleration of the particle after traversing a distance s.
Answer» `alpha^(2)SQRT((1)/(4)+ (s^(2))/(R^(2)))` `alpha^(2)sqrt((R^(2))/(4S^(2))+ (s^(2))/(R^(2)))` `alphasqrt((1)/(4)+ (s^(2))/(R^(2)))` `alphasqrt((R^(2))/(4s^(2))+ (s^(2))/(R^(2)))` ANSWER :A