A particle moves in a circular path such that its speed v varies with distance as v = alpha sqrt(s) where alpha is a positive constant. Find the acceleration of paarticle after trafversing a distance S?

A particle moves in a circular path such that its speed v varies with

1.	A particle moves in a circular path such that its speed v varies with distance as v = alpha sqrt(s) where alpha is a positive constant. Find the acceleration of paarticle after trafversing a distance S?
Answer» `ALPHA^(2)SQRT((1)/(4)-(S^(2))/(R^(2)))` `alpha^(2)sqrt((1)/(4)+(S^(2))/(R^(2)))` `alpha sqrt((1)/(2)+(S^(2))/(R^(2)))` `alpha^(2) sqrt((1)/(2)+(S^(2))/(R^(2)))` Answer :B