InterviewSolution
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InterviewSolution
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A particle moves in a circular path such that its speed `v` varies with distance `s` as `v = prop sqrt(s)` , where `prop` is a positive constant. Find the acceleration of the particle after traversing a distance `s`.A. `alpha^(2)sqrt(1/4-S^(2)/R^(2)`B. `alpha^(2)sqrt(1/4+S^(2)/R^(2)`C. `alphasqrt(1/4+S^(2)/R^(2)`D. `alpha^(2)sqrt(1/4+S^(2)/R^(2)` |
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Answer» Correct Answer - B `a=sqrt(a_(t)^(2)+a_(t)^(2))=sqrt(((dv)/(dt))^(2)+((v^(2))/(R))^(2)` |
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