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A particle moves in a straight line with a constant acceleration. It passing through a distance 135 m in t second. The value of t (in second) isA. 12B. 9C. 10D. `1.8` |
Answer» Correct Answer - B `upsilon^(2)=u^(2)+2as` `a=(upsilon^(2)-u^(2))/(2s)=((20)^(2)-(10)^(2))/(2xx135)=(300)/(270)=(10)/(9)ms^(-2)` From first equation of motion `upsilon=u+at rArr t(upsilon-u)/(a)=(20-10)/(10//9)=(10)/(10//9)=09s` |
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