A particle moves in the x-y plane under the action of a force →F=−

1.	A particle moves in the x-y plane under the action of a force →F=−2k sin kt(^i+^j) at any time t its linear momentum is given by PX = 2cos (kt) and PY = 2cos (kt)The angle between →Fand→P at time t is
Answer» A particle moves in the x-y plane under the action of a force $\to F = - 2 k s i n k t (^i +^j)$ at any time t its linear momentum is given by P_X = 2cos (kt) and P_Y = 2cos (kt)The angle between $\to F a n d \to P$ at time t is

A particle moves in the x-y plane under the action of a force →F=−2k sin kt(^i+^j) at any time t its linear momentum is given by PX = 2cos (kt) and PY = 2cos (kt)The angle between →Fand→P at time t is

Answer»

A particle moves in the x-y plane under the action of a force $\to F = - 2 k s i n k t (^i +^j)$ at any time t its linear

momentum is given by P_X = 2cos (kt) and P_Y = 2cos (kt)The angle between $\to F a n d \to P$ at time t is

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A particle moves in the x-y plane under the action of a force →F=−2k sin kt(^i+^j) at any time t its linear momentum is given by PX = 2cos (kt) and PY = 2cos (kt)The angle between →Fand→P at time t is

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