A particle moves in X-direction with acceleration f from rest. This acceleration changes according to f = f _(0) (1- (t)/(T)). and T are constant. t = 0 and for if any negative time interval if f = 0, then velocity of particle is ......

A particle moves in X-direction with acceleration f from rest. This ac

1.	A particle moves in X-direction with acceleration f from rest. This acceleration changes according to f = f _(0) (1- (t)/(T)). and T are constant. t = 0 and for if any negative time interval if f = 0, then velocity of particle is ......
Answer» `1/2 f _(0) T` `1/2 f _(0) t ^(2)` `f _(0) T` `f _(0) T ^(2)` SOLUTION :`f = f _(0) [1- (t)/(T)]` `f = 0 because f _(0) [1 + (t)/(T)] =0` `IMPLIES t = T` Now `f = (dV)/(dt)` `therefore(dV)/(dt) = f _(0) [1 - (t)/(T)]` `INT _(0) ^(V _(x)) dV = int _(t =0) ^(t =T) f _(0) [1- (t)/(T)]dt` `v _(x) = f _(0) [t - (t ^(2))/(2T) ] _(0) ^(T) ` `V_(x) = f_(0) [T- (T ^(2))/(2T)]` `V_(x) = f _(0) [T- (T)/(2)]` `V_(x) = 1/2 f_(0)T`