A particle moves in XY plane under the influence of a force such that its linear momentum is barP = A[(coskt)hati + (sin kt)(-hatj)] , where A and k are positive constants.

A particle moves in XY plane under the influence of a force such that

1.	A particle moves in XY plane under the influence of a force such that its linear momentum is barP = A[(coskt)hati + (sin kt)(-hatj)] , where A and k are positive constants.
Answer» The MAGNITUDE of the FORCE is Ak The angle between force and momentum is`pi/2` The angle between force and momentum is it `pi` The angle between acceleration and velocity VECTORS is ALWAYS `pi//2` Answer :A::B::D