A particle moves on a circle of radius r with centripetal accerleration as function of time as a_(e) = k^(2)rt^(2) where k is a positive constant. Find the resultant acceleration.

A particle moves on a circle of radius r with centripetal accerleratio

1.	A particle moves on a circle of radius r with centripetal accerleration as function of time as a_(e) = k^(2)rt^(2) where k is a positive constant. Find the resultant acceleration.
Answer» `KT^(2)` KR `krsqrt(k^(2)t^(4)+1)` `krsqrt(k^(2)t^(4)-1)` ANSWER :C