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A particle moves on a circle of radius r with centripetal accelration as function of time as `a_(c)=K^(2)rt^(2)` where k is a positive constant , find the resu ltant acceleration.A. `kt^(2)`B. `kr`C. `krsqrt(k^(2)t^(4)+1)`D. `krsqrt(k^(2)t^(2)-1)` |
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Answer» Correct Answer - c From given equation `omega=kt` `alpha=(domega)/(dt)=k, alpha_(t)=ralpha, alpha=sqrt(a_(c)^(2)+a_(r)^(2))` |
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