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An open merry go round rotates at an angular velocity `omega`.A person stands in it at a distance `r` from the rotational axis.It is raining and the rain drops falls vertically at a velocity `v_(0)`.How should the person hold an umbrella to protect himself from the rain in the best way.Angle made by umbrella with the vertical isA. `cot alpha=(v_(0))/(romega)`B. `tan alpha=(v_(0))/(romega)`C. `cot alpha=(romega)/(v_(0))`D. `tan alpha=(v_(0))/(romega)` |
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Answer» Correct Answer - a Let the velocity of the drops above the preson rel. to the merry go round be at an angle `alpha` to the vertical. This angle can be determined from the velocity triangle `v_(0)=v_("rel")+v_(m.g.r.)`, `v_("rel")=v_(0)-v_(m.g.r)` `v_(m.g.r)=romega, cot alpha=(v_(0))/(romega)` |
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