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A particle moves on the xy-pane such that its position vector is given by `vec(r)=3t^(2) hati-t^(3) hatj`. The equation of trajectory of the particle is given byA. `3x^(2)+16 y =0`B. `((3x)/2)^(4//3)+4y=0`C. `(x/32)^(3//2) +y=0`D. none of these |
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Answer» Correct Answer - 3 `vec(r)=2t^(2) hati-t^(3) hatj` `x=2t^(3) " " y=-t^(3)` `(x/2)^(1//2)=t" " y=-(x/2)^(3//2)` `(x/2)^(3//2) +y=0` |
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