A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals V_(0)then The total acceleration of the particle as function of velocity and distance covered

A particle moves with deceleration along the circle of radius R so tha

1.	A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals V_(0)then The total acceleration of the particle as function of velocity and distance covered
Answer» `a= SQRT(2)(V^(2))/(R)` `a= sqrt(2)(v)/(R)` `a= sqrt(2)(R)/(v)` `a= (2R)/(v)` Answer :A