A particle moving along a straight line with initial velocity u and accelerationa continues its motion for n seconds. What is the distance covered by it in the last n^(th) second?

A particle moving along a straight line with initial velocity u and ac

1.	A particle moving along a straight line with initial velocity u and accelerationa continues its motion for n seconds. What is the distance covered by it in the last n^(th) second?
Answer» SOLUTION :`S=ut+(1)/(2)at^(2)` Displacement in n seconds `=un+(1)/(2)an^(2)` Displacement in `(n-1)` seconds `=u(n-1)+(1)/(2)a(n-1)^(2)` Displacement in `n^(th)` SECOND = Displacement in n SECONS - displacement in `(n-1)` seconds. `therefore S_(n)=u+a(n-(1)/(2))`.