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A particle moving along a straight line with initial velocity u and acceleration a continuous its motion for n seconds. What is the distance covered by it in the last nth second? |
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Answer» Solution :`S=ut+1/2 at^2` Displacement in N SECONDS `=UN +1/2 an^2` Displacement in (n-1) seconds `=U(n-1)+1/2 a(n-1)^(2)` Displacement in nth seconds=Displacement in n seconds -displacement in (n-1) seconds. `S_n=u+a(n-1/2)` |
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