1.

A particle moving in the positive x-direction has initial v_(0). The particle undergoes retardation kv^(2), where it its instantaneous velocity. The velocity of the particle as a function of time is given by

Answer»

`v=v_(0)//(1+kv_(0)t)`
`v=(2v_(0))/(1+kt)`
`v=(v_(0))/(kt)`
`v=(v_(0))/((1+k^(2)v_(0)^(2)t))`

ANSWER :A


Discussion

No Comment Found