1.

A particle moving with shm has a period 0.001 s and amplitude 0.5 cm. Find the acceleration, when it is 0.2 cm apart from its mean position.

Answer»


SOLUTION :`ALPHA =(4pi^2//T^2)XXX= 4 xx3.14^2 (0.001)^2xx0.2 =7.897 xx10^4ms^(-2)`


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