1.

A particle of chagre equal to that of anelectron and mass 208 times the mass of the electron moves in a circular orbit around nucleus of chagre +3e. Assuming that the Bohar of the atom is applicableto this system ,(a) dervie am expression for the radius of the radius of the nth boharorbit ,(b) find the value of n for which the radius wavelenght of the raditatio emitted when the revolvingparticle jumps from the thrid orbit to the first.

Answer»


Solution :Centrifgal force =Electrostaticforce
(a) `(1)/(4lambdaepsilon_(0)).(3e.e)/(r^(2))=(208me.(V^(2))/(r))"".......(i)`
`mvr=(nh)/(2pi)""....(2)`
`r=(208)/(3e^(2)).(4piepsilon_(0))(v^(2)r^(2))`
`=(N^(2)h^(2))/(k.4pi^(2).3e^(2).208me)`
(b) `r=r_(0).n^(2)=6.9xx106n^(2)=0.53xx10^(-10)m`
`n^(2)~~625`
`n=25`
(c)`DELTAE=(1)/(2)m(V_(3)^(2)-V_(1)^(2))=(HC)/(lambda)`
putting the value of`V_(3)` and `V_(1)` from eq.(1) and (2) `lambda=55.2xx10^(-12)m`


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