A particle of charge q and mass m starts moving from the origin under the action of an electric field →E=E0^i and →B=B0^i with velocity →v=v0^j. The speed of the particle will become 2v0 after time

A particle of charge q and mass m starts moving from the origin under

1.	A particle of charge q and mass m starts moving from the origin under the action of an electric field →E=E0^i and →B=B0^i with velocity →v=v0^j. The speed of the particle will become 2v0 after time
Answer» A particle of charge $q$ and mass $m$ starts moving from the origin under the action of an electric field $\to E = E_{0}^i$ and $\to B = B_{0}^i$ with velocity $\to v = v_{0}^j$ . The speed of the particle will become $2 v_{0}$ after time

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A particle of charge q and mass m starts moving from the origin under the action of an electric field →E=E0^i and →B=B0^i with velocity →v=v0^j. The speed of the particle will become 2v0 after time

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