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A particle of mass 0.1 kg executes SHM under a force F =-10x (N). Speed of particle at mean position is 6m//s. Find its amplitude of oscillations |
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Answer» SOLUTION : From conservation of mechanical energy. `(1)/(2)kA^(2)= (1)/(2)MV^(2)` or `A= vsqrt((m)/(K))= 6sqrt((0.1)/(10))= (6)/(10)= 0.6 m` |
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