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A particle of mass 0.1 kg executes SHM under a force F =-10x (N). Speed of particle at mean position is 6m//s. Find its amplitude of oscillations |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : From conservation of mechanical energy. <br/> `(1)/(2)kA^(2)= (1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)` or `A= vsqrt((m)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>))= 6sqrt((0.1)/(10))= (6)/(10)= 0.6 m`</body></html> | |